File:VFPt superconductor cylinder B-field.svg
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Size of this PNG preview of this SVG file: 600 × 600 pixels. Other resolutions: 240 × 240 pixels | 480 × 480 pixels | 768 × 768 pixels | 1,024 × 1,024 pixels | 2,048 × 2,048 pixels.
Original file (SVG file, nominally 600 × 600 pixels, file size: 31 KB)
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Summary
[edit]| Description |
English: Deformation of a previously homogeneous magnetic field around an ideal diamagnetic infinite cylinder with very small permeability (e.g. a superconductor). Inside the cylinder the B-field vanishes, but the H-field is finite and uniform. The magnetic field lines are accurately computed. |
| Date | |
| Source | Own work |
| Author | Geek3 |
| Other versions | VFPt superconductor ball B-field.svg, VFPt superconductor cylinder B-field potential+contour.svg |
| SVG development |  This plot was created with VectorFieldPlot. |
| Source code | Python code# paste this code at the end of VectorFieldPlot 2.4
doc = FieldplotDocument('VFPt_superconductor_cylinder_B-field',
width=600, height=600, commons=True)
field_direction = [0.0, -1.0]
r = 1.2
field = Field([['homogeneous', {'Fx':field_direction[0], 'Fy':field_direction[1]}],
['dipole2d', {'x':0, 'y':0, 'px':-2*pi*r**2*field_direction[0],
'py':-2*pi*r**2*field_direction[1]}]])
# draw the superconducting cylinder
cylinder = doc.draw_object('g', {'id':'metal_cylinder'})
def triangle_path(phi1, phi2, r):
x1, y1 = r * cos(radians(phi1)), r * sin(radians(phi1))
x2, y2 = r * cos(radians(phi2)), r * sin(radians(phi2))
d = 'M {:.4f},{:.4f}'.format(x1, y1)
d += ' A {:.4f},{:.4f} 0 0 1 {:.4f},{:.4f}'.format(r, r, x2, y2)
d += ' L {:.4f},{:.4f}'.format(-x2, -y2)
d += ' A {:.4f},{:.4f} 0 0 0 {:.4f},{:.4f}'.format(r, r, -x1, -y1)
d += ' L {:.4f},{:.4f} Z'.format(x1, y1)
return d
def grey(bright):
return '#' + 3 * ('%02x' % int(256. * bright - 0.5))
doc.draw_object('circle', {'cx':0, 'cy':0, 'r':'{:.4f}'.format(r),
'style':'fill:' + grey(0.75) + '; stroke:none'}, group=cylinder)
for phi0 in [0]:
ncolors = 25
for a in sc.linspace(.5 / ncolors, 1 - .5 / ncolors, ncolors):
bright = 0.75 + 0.15 * a
phi1 = phi0 - 60 * (acos(2. * a - 1) / pi)**1.5
phi2 = phi0 + 60 * (acos(2. * a - 1) / pi)**1.5
d = triangle_path(phi1, phi2, r)
doc.draw_object('path', {'d':d,
'style':'fill:' + grey(bright) + '; stroke:none'}, group=cylinder)
doc.draw_object('circle', {'cx':0, 'cy':0, 'r':str(r),
'style':'fill:none; stroke:black; stroke-width:0.02'}, group=cylinder)
nlines = 20
for i in range(nlines):
a = -3 + 6 * (0.5 + i) / nlines
line = FieldLine(field, [a, 8], maxr=16, pass_dipoles=1)
doc.draw_line(line, arrows_style={'dist':4,
'offsets':{'leave_image':0.3, 'enter_image':0.3},
'fixed_ends':{'leave_image':True, 'enter_image':True} })
doc.write()
|
Licensing
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I, the copyright holder of this work, hereby publish it under the following license:
This file is licensed under the Creative Commons Attribution-Share Alike 4.0 International license.
- You are free:
- to share – to copy, distribute and transmit the work
- to remix – to adapt the work
- Under the following conditions:
- attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use.
- share alike – If you remix, transform, or build upon the material, you must distribute your contributions under the same or compatible license as the original.
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 12:47, 13 October 2019 | | 600 × 600 (31 KB) | Geek3 (talk | contribs) | User created page with UploadWizard |
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